Question
'r' is one of the roots of equation (r -
1)p2Â - (5r + 2)p + 12 = 0 and sum of roots is (32/5), Determine the two roots of the equation.Solution
ATQ, Let another root is 'q'. So, r + q = [5r + 2]/[r - 1] = 32/5 So, 25r+10 = 32r - 32 Or, 7r = 42, r = 6 So, another roots is (32/5) - 6 = 2/5
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