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    Question

    I. 3x2 – 17x + 10 = 0 II.

    y2 – 17y + 52 = 0 In the following questions, two equations numbered I and II are given.  You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x < y Correct Answer Incorrect Answer
    C If x ≥ y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or Relationship between x & y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 3x2 – 17x + 10 = 0 => 3x2 – 15x – 2x + 10 = 0 => 3x(x – 5) – 2(x - 5) = 0 => (x – 5) (3x - 2) = 0 => x = 5, 2/3 II. y2 – 17y + 52 = 0 => y2 – 13y - 4y + 52 = 0 => y (y – 13) - 4(y – 13) = 0 => (y – 13) (y - 4) = 0 => y = 13, 4 Hence, x = y or the relationship cannot be established.

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