Question
(I) `3p^2 + 17p + 10 = 0` (II)
>`10q^2 + 9q + 2 = 0` In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if; (1) p>q, (2) p<q, (3) p=q, (4) p ≥ q (5) p ≤ qSolution
I. `3p^2 + 17p + 10 = 0` , or 3p(p + 5) + 2(p + 5) = 0, Or (3p+ 2)(p + 5) = 0, p = - `2/3` , -5 II. `10q^2 + 9q + 2 = 0` , or `10q^2 + 5q + 4q + 2 = 0` , 5q(2q + 1) + 2(2q + 1) = 0, or (5q + 2)(2q + 1) = 0 , q = `2/5, 1/2` , Hence, q > p
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