How many coins does W have?

Solution

W’s brother S, sits on the immediate left of his mother who has 6 coins. P is the father of V and only one person sits between W’s mother and T. U, who is sister of V, has 7 coins and is not an immediate neighbour of W’s husband. V is father of R and is not an immediate neighbour of T. P is married to W. By the statement ‘only one person sits between W’s mother and T’, we find that Q is W’s mother and T is S’ daughter.  No female is an immediate neighbour of Q, who sits at the corner of the table. Q sits second to the left of W’s husband who has neither 4 nor 7 coins. Only one person is sitting between P and U. S’s daughter sits second to the right of U and on the immediate left of that person who has 3 coins. T sits on the immediate right of the person who has 2 coins. S, sits on the immediate left of his mother who has 6 coins. V is not an immediate neighbour of T. So, V can sit at immediate right or immediate left to P. If V sits immediate right to P, and as we know that W is female so she sit at immediate left to T. We know that V sits second to the right of the person who has 8 coins. By this statement this condition is not possible.   If V sits immediate left to P, so W will sit at immediate right to P. Then R will sit at immediate left to T. Further V sits second to the right of the person who has 8 coins. It is given that T has 1 coin and that of U is 7. So V will have 4 and P will have 5 coins