Question
Item ‘X’ had a cost price of Rs. 800 and it was
marked up by 25%. It was later sold after giving a discount of Rs. 40. Another item ‘Y’ was sold for Rs. 900 at a loss of 10%. What is the ratio of the cost price of item ‘Y’ to the selling price of item ‘X’?Solution
ATQ,
Marked price of item ‘X’ = 800 × 1.25 = Rs. 1,000 Selling price of item ‘X’ = 1,000 – 40 = Rs. 960 Cost price of item ‘Y’ = 900 / 0.90 = Rs. 1,000 So, required ratio = 1000:960 = 25:24
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
I. 6x2 – 7x - 20 = 0
II. 3y2Â - y - 14 = 0
I. 2y2 + 13y + 15 = 0
II. 2x2 + 11 x + 12 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
 If x satisfies x² – 14x + 40 = 0, find x.
I. 2x2 – 5x – 12 = 0
II. 2y2 + 13y + 20 = 0