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    Question

    I. 88x² - 13 x – 56 = 0 II. 15 y²

    + 41 y + 28 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x>y Correct Answer Incorrect Answer
    B if x≥y Correct Answer Incorrect Answer
    C if x Correct Answer Incorrect Answer
    D if x ≤y Correct Answer Incorrect Answer
    E If x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 88x² - 13 x – 56 = 0 88x² - 77 x + 64 x – 56 = 0 11 x(8 x – 7) + 8 (8x – 7) = 0 (11 x + 8) (8 x – 7) = 0 x = 7/8, -8/11 II. 15 y² + 41 y + 28 = 0 15 y² + 21 y + 20 y + 28 = 0 3 y(5 y + 7) + 4 (5 y + 7) = 0 (3 y + 4) (5 y + 7) = 0 y = -4/3, -7/5 Hence, x>y

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