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      Question

      I. 63x² + 37 x – 40 = 0 II. 15 y² + 29 y + 12

      = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
      A if x>y Correct Answer Incorrect Answer
      B if x≥y Correct Answer Incorrect Answer
      C if x Correct Answer Incorrect Answer
      D if x ≤y Correct Answer Incorrect Answer
      E If x=y or the relationship cannot be established Correct Answer Incorrect Answer

      Solution

      I. 63x² + 37 x – 40 = 0 63x² - 35 x + 72 x – 40 = 0 7 x(9 x – 5) + 8(9 x – 5) = 0 (7 x + 8) (9 x – 5) = 0 x = 5/9, -8/7 II. 15 y² + 29 y + 12 = 0 15 y² + 20 y+ 9 y + 12 = 0  5 y(3 y + 4) + 3(3 y + 4) = 0 (5 y + 3) (3 y + 4) = 0 y = -3/5, -4/3 Hence, relationship cannot be established between x and y

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