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    Question

    Average of eleven consecutive numbers is 42. Find the

    sum of smallest and largest number.
    A 80 Correct Answer Incorrect Answer
    B 82 Correct Answer Incorrect Answer
    C 84 Correct Answer Incorrect Answer
    D 86 Correct Answer Incorrect Answer

    Solution

    Let the numbers be (a - 5), (a - 4), (a - 3), (a - 2), (a - 1), a, (a + 1), (a + 2), (a + 3), (a + 4) and (a + 5).
    So, (a - 5 + a - 4 + a - 3 + a - 2 + a - 1 + a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5) ÷ 11 = 42
    Or, (11a/11) = 42
    Or, 'a' = 42
    Required sum = a - 5 + a + 5 = 2a = 2 × 42 = 84

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