Question
What was the cost price of an item that a shopkeeper
sold at a 20% discount after initially marking it up by 60%, resulting in a profit of Rs. 126?Solution
ATQ, Let cost price of the article is Rs. 100x Marked price of the article = 1.60 × 100x = Rs. 160x Selling price of the article = 0.80 × 160x = Rs. 128x According to question; 128x – 100x = 126 Or, 28x = 126 Or, x = 4.5 Cost price of the article = 4.5 × 100 = Rs. 450
More Profit and loss Questions
cot 13Ëš Â
 cot 14˚  ...If (sin A + cos A) = √3 cos (90° - A), then find the value of cot A.
- If 2cos²A + 3sin²A = 13/5, then find the value of (sec²A - 1)
If sin (2x + 50) o = cos (2y - 50) o, such that, 0o < x + y < 90o, then find the value of tan(x + y) .
- If sin(A + B) = √3/2 and cos(A + 2B) = 0, where 0° < A, B < 90°, then find the value of tan(2A).
If cos 2A = 1, then find cos A
What is the simplified value of the given expression?
3(sin² 50° + sin² 40°) + 6sin 30° - (3sec 60° + cot 45°)
Find the value of `1/2`  cosec 10  - `2/(cosec 70)`  ?
Find the maximum value of 20 sin A + 9 cos A.
- If sin (3A − 4B) = (1/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
Relevant for Exams:
