Question
A mobile phone was tagged 25% above its cost price. A
discount was applied, resulting in a loss of 10%. Now, if the same discount is maintained, by what percentage is the selling price less than the new marked price when the loss is 5%?Solution
ATQ,
Let the cost price of the mobile phone be Rs. x Therefore, marked price of the mobile phone = Rs. 1.25x Selling price of the mobile phone at 10% loss = Rs. 0.90x Discount given on the mobile = 1.25x – 0.90x = Rs. 0.35x Selling price of the mobile at 5% loss = Rs. 0.95x Marked price of mobile keeping the discount same = 0.95x + 0.35x = Rs. 1.30x Required percentage = (0.35x / 1.30x) × 100 = 26.92%
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 97x² - 436x + 339 = 0
Equation 2: 103y² - 460y + 357 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 2x² + 11 x + 15 = 0  Â
II. 2y² - 19 y + 44 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I. 3y2 + 16y + 16 = 0
II. 2x2 + 19x + 45 = 0
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
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