Question
A dishonest fruit seller sells fruits at 8 % loss. If he
uses 860gm weight in place of 1kg weight, then what is his profit percent?Solution
CP of 1000gm = Rs 100 SP of 860gm = Rs 100 – Loss = 100 – 8 = Rs 92 (as 8% on 100 = Rs 8) Actual CP = 86 Profit % = `(92-86)/86` × 100 = `6.7 = 7 %`
Solve the inequality:
(x − 1)/(x + 2) > 2.
Which of the following represents the solution set?
(A) x < −5
(B) −5 < x <...
If (6m – 5n) 2  = 7 and 30mn = 60, then find the value of (6m + 5n) 2  + 16mn.
- Find the value of (21)³ + (- 12) ³ + ( - 9)³.
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
- If (m + n + o) = 16 and (mn + no + om) = 80, then find the value of (m² + n² + o²).
If (a2 + 1/a2) = 11, then find the value of (a3 - 1/a3).
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf x/y = 5/3, Find (x+y)/(x-y)?
