Question
Two parallel wires of length 10 cm each are separated by
a distance of 0.5 cm in a liquid. If the distance between them is increased by 2 mm, how much work is done? (Surface tension = 72 dyne/cm)Solution
W=T×ΔA ΔA=2×length×Δd Substituting values: W=72×2×10×0.2=288 ergs
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