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ATQ, The sum was to be divided in the ratio 3:4:5:8. Let the sum of A, B, C, and D is 3x,4x,5x, and 8x respectively. According to the question, we get 20x = 8720 x=436 so, we get A = 1308; B = 1744; C = 2180; D =3488 But by mistake it was divided in the ratio; 1/3: 1/4: 1/5: 1/8 By Equating, the ratio will be 40: 34: 24: 15. The new sum of A, B, C and D will be 40x, 30x, 24x and 15x respectively. Solving in the same way, we get A =3200, B = 2400, C = 1920 and D = 1200 So, we can say D got 2288 less.
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