Question
In a 280-litre mixture (milk + water), the ratio of
quantities of milk and water is 3:4, respectively. How much water should be added to this mixture such that the ratio of the quantity of milk to that of water in the resultant mixture becomes 2:3?Solution
Initially, Quantity of milk in the mixture = {(3 × 280)/7} =120 liters Quantity of water in the mixture = {(4 × 280)/7} = 160 liters Let the quantity of water be added to the mixture = ‘x’ liters ATQ, {120/ (160 + x)} = 2/3 Or, 360 = 320 + 2x Or 2x = 40 x= 20 liters
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2