Question
A box contains 4 red, 5 blue and 3 green balls. Two
balls are drawn at random without replacement. What is the probability that both balls are of the same colour?Solution
ATQ, Total balls = 4 + 5 + 3 = 12. Total ways to choose 2 balls = C(12,2) = 66. Ways to choose 2 of same colour: Red: C(4,2) = 6 Blue: C(5,2) = 10 Green: C(3,2) = 3 Total favorable = 6 + 10 + 3 = 19. Probability = 19/66.
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