Question
A bag contains 7 green balls, 5 blue balls, and 10
yellow balls. A box contains 3 green balls and 8 yellow balls. A ball is randomly drawn from the box and put into the bag, and then a ball is randomly drawn from the bag. Find the probability that the ball is of yellow color.Solution
ATQ, Bag: 22 balls (10 yellow). Box: 11 balls (8 yellow, 3 green). Case 1: A yellow ball is added to the bag. Probability of drawing yellow from the box: 8/11. Bag ha 11 yellow out of 23 balls: 11/23. Contribution: 8/11, 11/23 = 88/253.
Case 2: A green ball is added to the bag. Probability of drawing green from the box: 3/11 Bag has 10 yellow out of 23 balls = 10/23 Contribution: 3/11, 10/23 = 30/253 .
Total Probability:
More Probability Questions
- Simplify the following expression:
(48% of 800 × 3) ÷ 6 + 440 ÷ √25 - 14² 12.5% of (100 + ?) = 40
3% of 3000 x ?% of 2000 = 3600
- Determine the value of ‘x’ if (7 × 256 – 525 ÷ 21) ÷ 28 = √2500 – x.
- Find the simplified value of following expression:
0.998 + 0.882 + 0.12 What will come in place of (?) in the given expression.
(3/4 of 64) + (1/2 of 48) = ?24 × √? + 4008 ÷ 24 = 40% of 200 + 327
What is the value of (152+82) ÷17
- What will come in the place of question mark (?) in the given expression?
What will come in place of (?) in the given expression.
625 + 196 – √256 = ?
Relevant for Exams:
