Question
Two Dice are thrown simultaneously. Find the probability
that the number on the first dice is more than the number of 2nd Dice.Solution
When two Dice are thrown simultaneously then – Total number of possible cases =62 =36 Number of favorable cases – (2,1) (3,1) (3,2) (4,1) (4,2) (4,3) (5,1) (5,2) (5,3) (5,4) (6,1) (6,2) (6,3) (6,4) (6,5) Total number of favorable cases = 15 Probability = 15/36 =5/12
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