Question
A letter is taken out at random from âROORKEEâ and
another is taken out from âBOOKKEEPERâ. The probability that they are the same letter isÂSolution
Hence, B and P are not common and same letters can be R, O, K, E Probability of choosing R = (²Câ)/(âˇCâ)  à  (šCâ)/(šâ°Câ) = 1/35 Probability of choosing O = (²Câ)/(âˇCâ)  à (²Câ)/(šâ°Câ) = 2/35 Probability of choosing K = 1/(âˇCâ) Ă Â (²Câ)/(šâ°Câ) = 1/35 Probability of choosing E = (²Câ)/(âˇCâ)  à (ÂłCâ)/(šâ°Câ) = 3/35 Hence, Required Probability = 1/35+  2/35+  1/35+  3/35 = 7/35 = 1/5
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