Hence, B and P are not common and same letters can be R, O, K, E Probability of choosing R = (²C₁)/(⁷C₁) × (¹C₁)/(¹⁰C₁) = 1/35 Probability of choosing O = (²C₁)/(⁷C₁) × (²C₁)/(¹⁰C₁) = 2/35 Probability of choosing K = 1/(⁷C₁) × (²C₁)/(¹⁰C₁) = 1/35 Probability of choosing E = (²C₁)/(⁷C₁) × (³C₁)/(¹⁰C₁) = 3/35 Hence, Required Probability = 1/35+ 2/35+ 1/35+ 3/35 = 7/35 = 1/5
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I. Z is father of A and brother of B
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The question given below consists of two statements numbered I and II below them. You have to decide whether the data provided in the statements are su...
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I.B is wife of C. D is wife of E. F is sister of G, who is daughter of E.
II. E is husband of D, who is daughter &n...
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How is C related to D?
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