Question
In a box, there are 6 red balls, 8 green balls, and 10
blue balls. If one ball is drawn at random, what is the probability that the ball drawn is either red or green?Solution
The total number of balls = 6 + 8 + 10 = 24 The number of favorable outcomes (red or green) = 6 + 8 = 14 The probability is given by: Probability = (Favorable Outcomes) / (Total Outcomes) Probability = 14/24 = 7/12 Correct Option: a) 7/12
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 31x² - 170x + 216 = 0
Equation 2: 22y² - 132y + ...
i) p2+p=56 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
II) q2-17q+72=0
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
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