Question
Bag A contains 4 blue and 5 green balls, while Bag B
contains 6 blue and 10 red balls. If one ball is drawn from bag 'A' and bag 'B', respectively, at random, then what is the probability that both balls drawn are blue?Solution
Probability of drawing a blue ball from Bag A = (4/9)
Probability of drawing a blue ball from Bag B = (6/16) = (3/8)
Required probability = (4/9) × (3/8) = (12/72) = (1/6)
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