Question
A bag contains 5 brown balls, 6 white balls and 9 red
balls. Three balls are drawn at random. Find the probability that at least two balls are red.Solution
Total = 5 + 6 + 9 = 20
Required probability = (Two red and one other) + (Three red)
= 3 × [(9/20) × (8/19) × (11/18)] + (9/20 × 8/19 × 7/18)
= (2376/6840) + (504/6840)
= (2880/6840) = (24/57)
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Simplify the following expression -:
120 + 480 ÷ 16 × 6 + {(240 ÷ 2.5) × 5 + 120} ÷ 5
88.88% of 539.712 + 14.28% of 350.12 = ? + 20.18 * 9.91
115, 138, 163, 190, 219, ?
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