Question
5 boys and 3 girls are to be seated on chairs arranged in a
row. If the arrangement is made at random, find the probability that no two girls will be seated next to one another.Solution
8 people can be seated on 8 chairs in 8! ways.
No two girls will be seated next to one another, so the arrangement would be like:
__ B __ B __ B __ B __ B __
5 boys can be seated at 5 places in 5! Ways. After this, 3 girls can be seated in the remaining 6 places in 6 P 3  ways.
Favorable outcomes= 5! XÂ 6 P 3 .
Probability = (5! x 6!)/(3! x 8!) = 5/14
(15/8) x [6924 – 2124] + 910 = ? + 190
What will come in the place of question mark (?) in the given expression?
(70 × 8 ÷ 10) × 5 = ?
192.251 + 326.233 + 125.021 + 19.273 = ?
12 × 6 + 24 – 36 of 5 + 160 = ?
? = (25% of 20% of 800) × 8 – 25% of 260
30% of 600 –
60 % of 640 - 57 × 2 - 1520 / 38 = ?
17.5% of 400 – 24% of 150 = ?
1440 ÷ 12 + 540 ÷ √36 + ? = 180 * 3
4567.89 - 567.89 - 678.89 = ?
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