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(x + 2 – x)/(3x + 12) = 1/8
Or, 3x + 12 = 16
Or, x = 4/3
So, desired ratio = (4/3 + 10)/(16) = 34/48 = 17/24
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
Equation 1: x² + 16x + 63 = 0
Equation 2: y² + 10y + 21 = 0
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
Equation 1: x² - 144x + 5184 = 0
Equation 2: y² - 130y + 4225 = 0
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
I. p2 – 2p – 15 = 0
II. q2 + 4q – 12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y +...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
(i) x² – 3x – 40 = 0
(ii) y² + 11y + 30 = 0