Question
Three fair coins are tossed simultaneously. Find the
probability that at least two heads appear.Solution
Sample space of three coins: 2³ = 8 outcomes. List outcomes (H = head, T = tail): HHH HHT HTH THH HTT THT TTH TTT “At least two heads” means 2 or 3 heads. Count favourable outcomes: Exactly 2 heads: HHT, HTH, THH → 3 outcomes Exactly 3 heads: HHH → 1 outcome Total favourable = 3 + 1 = 4 Probability = favourable / total = 4 / 8 = 1 / 2 Answer: 1/2.
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