Question
6 Boys and 5 Girls sat in a row randomly. What is the
probability that no 2 Girls are together?Solution
6 Boys and 5 Girls, i.e., a total of 11 people can be arranged in 11!/6!5! ways or, 462 ways.
For no 2 Girls to sit together, arrangement can be done in the following way: [B are Boys]
_ B _ B _ B _ B _ B _B_
There are 7 spaces that can be taken up by 5 Girls so that no 2 of them sit together.
Number of ways =Â 7 C 5 Â = 21.
Required probability = 21/462 = 1/22
2387.56 + ? – 2248.14 = 1765.45 – 1574.23
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
What approximate value will replace the question mark (?) in the following?
? = 1...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
In a village election, 300 votes were declared invalid. The winning candidate secured 60% of the valid votes and won by a margin of 1,500 votes. Find th...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
What is the area (in cm²) of a square inscribed in a circle with a radius of 10√2 cm?
20% of 80 × 26% of 65 = ?
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