Question
6 Boys and 5 Girls sat in a row randomly. What is the
probability that no 2 Girls are together?Solution
6 Boys and 5 Girls, i.e., a total of 11 people can be arranged in 11!/6!5! ways or, 462 ways.
For no 2 Girls to sit together, arrangement can be done in the following way: [B are Boys]
_ B _ B _ B _ B _ B _B_
There are 7 spaces that can be taken up by 5 Girls so that no 2 of them sit together.
Number of ways =Â 7 C 5 Â = 21.
Required probability = 21/462 = 1/22
More Probability Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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