Question
Two numbers are chosen at random without replacement from
the set of first 20 natural numbers. Find the probability that both the numbers are even.Solution
Total numbers = 20
Even numbers = 10
Required probability = ( 10 C 2 ) / ( 20 C 2 ) = 45 / 190 = 9/38
The question consists of two quantities, choose the correct option which represents the. correct relation between Quantity I and Quantity II.
...
Quantity I. value of m is 5/6 of x. Given that x - √576 = 0
Quantity II. Value of y in √15 y - 5 = 25
What is the larger number?
Quantity I. Difference between the two numbers is 21 and LCM and HCF of those numbers are 70 and 7 respectively.
<...Pawan, Qureshi, and Ram started a business with initial investments of Rs. (x + 1500), Rs. x, and Rs. (x - 1000), respecti...
Direction: The question consists of two quantities, choose the correct option which represents the correct relation between Quantity I and Quanti...
Quantity I: In how many ways can a committee consisting of 2 Managers and 5 Team Leaders be selected from a group of 7 Managers ...
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
In the following question, read the given statement and compare Quantity I and Quantity II on its basis. (Only quantity is to be considered)
The current ages of three friends, Aman, Bheema, and Chintu, are represented as (p−3), p, and (2p−6) years, respectively. It ...
Quantity-I: 'A' can do 60% of work in 36 hours. Find the value of 'Y' if the time taken by him to complete the whole work is 'Y' hours.
Quantit...
