Question
A box contains ‘x + 1’ green balls, ‘x + 4’ blue
balls and ‘x – 2’ yellow balls. If the probability of drawing a yellow ball is 1/30 less than the probability of drawing a blue ball, find the value of ‘x’.Solution
According to question: (x + 4)/(3x + 3) – (x – 2)/(3x + 3) = 1/30 (x + 4 – x + 2)/(3x + 3) = 1/30 6/(3x + 3) = 1/30 3x + 3 = 180 3x = 177 x = 59
Statements: E # L, L @ U, U $ N, N % K
Conclusions: I. K @ U II. K % U III. E @ U
...Statements: L ≥ F = Z < P, Q ≥ A > C = P
Conclusions:
I. A > F
II. Q > Z
Statement: E ≤ F; E ≤ H; F = P; H < S
Conclusion:
I. S ≤ F
II. P ≥ S
Statements:
P = G > Q = C > B; J < Z ≤ C
Conclusions:
I. Q > Z
II. B ˃ J
Statements: Â S * K, T $ K, K @ B
Conclusions:Â Â Â Â Â a) S $ BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â b) S @ B
...Statements: P > Q ≥ R < S < U > V > T > W > X > Y
Conclusion:
I. Q > T
II. Q ≤ T
Statements: B > C ≥ D ≥ E; G ≤ F = E; I < H ≤ G
Conclusions:
I. C > H
II. I < E
III. B ≥ F
Statements:Â Â Â Â Â Â T @ V % Z #Â C & B $ SÂ # E; W $ Z @ C
Conclusions :Â Â Â Â Â I. E @ ZÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. S # WÂ Â Â ...
Which of the following symbols should replace the sign (@) and (%) respectively in the given expression in order to make the expression C ≥ G and A > ...
Statements:Q ≥ R,R < S,S < T
Conclusions: I. T > R II. Q ≥ T