Question
Two cards are drawn together from a pack of 52 cards.
The probability that one is a club and one is a diamond?Solution
Solution: Here, the ‘one-club’ card has to be drawn from 13 club cards. So, its events = 13C1 And ‘one-diamond’ card has to be drawn from 13 diamond cards. So, its events = 13C1 So, concerned events = 13C1 × 13C1 Total events (as two cards are to be drawn from 52 cards) = 52C2 So, P(E) = 13C1 × 13C1 / 52C2 = 13/102
342 – 232 + 256 – 104 = ?
14 × 11 + 25 – ? = 21% of 300
2850 ÷ 2.5 - ? × 42 = 300
What will come in the place of question mark (?) in the given expression?
(72 × 6 ÷ 12) × 6 = ?
Find the value of 325 × 5 + 31 × 21 – 22 × (63 − 52).
√? = 80% of 720 - 22% of 2500
5555 ÷ 11 ÷ 5 = 100 + ?
- What will come in place of (?) in the given expression.
[45 + (36 ÷ 6)] × 2 – 10 = ? (23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
If a³ - b³ = (a - b)(a² + ab + b²), find a³ - b³ when a = 10 and b = 4.
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