Question
Two cards are drawn together from a pack of 52 cards.
The probability that one is a club and one is a diamond?Solution
Solution: Here, the ‘one-club’ card has to be drawn from 13 club cards. So, its events = 13C1 And ‘one-diamond’ card has to be drawn from 13 diamond cards. So, its events = 13C1 So, concerned events = 13C1 × 13C1 Total events (as two cards are to be drawn from 52 cards) = 52C2 So, P(E) = 13C1 × 13C1 / 52C2 = 13/102
What approximate value will replace the question mark (?) in the following?
? = 2...
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?
19.912 - (599.98 - 96.01 ÷ 3.01) ÷ 1.98 = ? + √254
319.995 × 15.98 ÷ 4.002 - ? × 7.95 = 1679.89 ÷ 2.005
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
What approximate value will replace the question mark (?) in the following?
24.99...
A Sales Executive gets a commission on total sales at 10%. If the sale is exceeded Rs.15,000 he gets an additional commission as a bonus of 5% on the ex...
64.64% of 419.89 + 116.61 = ? x 12.89
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