Solution: Here, the ‘one-club’ card has to be drawn from 13 club cards. So, its events = 13C1 And ‘one-diamond’ card has to be drawn from 13 diamond cards. So, its events =13C1 So, concerned events =13C1×13C1 Total events (as two cards are to be drawn from 52 cards) = 52C2 So, P(E) =13C1×13C1/52C2= 13/102
If A = 26 and T = 7, then AUTHENTIC = ?
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