Question
Two hats are picked at random, what is the probability
that one is blue and one is yellow? A box contains 6 red, 4 blue, 2 green and 4 yellow hats.Solution
Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 hats out of 16 = ¹⁶C_2 = (16 × 15 )/( 2 × 1) = 120 Let E= event of drawing two hats so that one is blue and one is yellow. n(E) = ⁴C_1×⁴C_1= 4 × 4= 16 ∴ P (E) = (n(E))/(n(S)) = 16/120 = 2/15
I. 3y2 + 13y - 16 = 0
II. 3x2 – 13x + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 31x² - 170x + 216 = 0
Equation 2: 22y² - 132y + ...
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 2y2 + 11y + 15 = 0
II. 3x2 + 4x - 4= 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
