Two cards are drawn together from a pack of 52 cards. The probability that one is a club and one is a diamond?
Solution: Here, the ‘one-club’ card has to be drawn from 13 club cards. So, its events = 13C1 And ‘one-diamond’ card has to be drawn from 13 diamond cards. So, its events = 13C1 So, concerned events = 13C1 × 13C1 Total events (as two cards are to be drawn from 52 cards) = 52C2 So, P(E) = 13C1 × 13C1 / 52C2 = 13/102
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