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Let the number of grey and white cars be ’x’ each. Then the number of silver cars will be ‘x + 3’. So, (x + 3) + x + x = 30 3x = 27 x = 9 So, number of silver, grey and white cars is 12, 9 and 9 respectively. Required probability = P (at least one of them is silver) = 1 – P (none of them is silver) = 1 – (18/30) × (17/29) × (16/28) = 1 – (204/1595) = (1391/1595)
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