Question
A contains X green Balls, '7 Red Balls, and 5 Yellow
Balls. The probability to pick Green Ball at random is 3/5. Another Bag B contains ‘6 green Balls, ‘x – 3’ Yellow Balls and x - 4' Red Balls. If two balls are picked one after the other from Bag B at random then what is the probability for the Balls to be Red?Solution
x/(7+x+5) = 3/5 X = 18 Now, In Bag B: Red balls = 18 – 4 = 14 Yellow balls = 18 – 3 = 15 Green ball = 6 Required Probability = 14/35 × 15/35 = 6/35
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