Question
Amar tells the truth in 75% of cases and Akbar in 25% of
cases.Find the probability that at least one of them tells the truth in a trial.Solution
ATQ,
Amar tells truth = 0.75
→ lies = 0.25
Akbar tells truth = 0.25
→ lies = 0.75
At least one truth:
P = 1 – P(both lies)
P(both lies) = 0.25 × 0.75 = 0.1875
P(at least one truth) = 1 – 0.1875 = 0.8125 = 13/16
41 28 ? 15 67 2
3 15 35 63 99 ?
4                14                  130                     512                �...
1 1 8 4 27 9 81
...Select the number from among the given options that can replace the question mark (?) in the following series.
24, 35, 51, 73, 102, ?
4 5 12 39 160 ?
...10, 22, 46, ?, 130, 190
3  16  22  ?   98   206
542Â Â Â Â Â Â 541Â Â Â Â Â Â Â 532Â Â Â Â Â Â Â 507 Â Â Â Â Â Â Â 458Â Â Â Â Â Â Â ?
...If   314     306      x      269       394    178    1480
Then, 1/3 x + 2x - x = ?
...
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