Question
A bag contains 7 blue balls, 3 red balls and remaining
were black balls. Probability of drawing a black ball from the bag is (4/9) . Find the number of black balls in the bagSolution
ATQ, Let the number of black balls be 'y'. ATQ, y ÷ (y + 7 + 3) = (4/9) Or, 9y = 4 X (y + 10) Or, 9y = 4y + 40 Or, 5y = 40 So, 'y' = 8
More Probability Questions
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
(?)2 + 4.113 = 24.92 – 32.03Â
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
58.03% of 1499.99 - ? % of 699.95 = 394.04
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
What will be the approximate value of the following questions.
(√143.74 + 29.89% of 720.27) × (5/9 of 539.79) = ?
11.06 2 – 7.12 × 4.88 + 9.96 = 12.22 × ?Â
? = 49.97% of 38.09% of 1998.95
5.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
(5/9 of 2699.81) + (49.88% of 144.18) - (2/7 of 489.77) = ?
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