Question
Three persons. A, B and C. are given the same puzzle to
solve. The probability that A, B and C will solve the puzzle is. 3/5., 2/3., and 1/4respectively. Find the probability that exactly one of them will not solve the puzzleSolution
Probability of A solving the puzzle = 3/5 Therefore the probability of A not solving the puzzle = 1- (3/5) = 2/5 Probability of B solving the puzzle = 2/3 Therefore. Probability of B not solving the puzzle = 1/3 Probability of C solving the puzzle = ¼ Probability of C not solving a puzzle= ¾ Therefore, required probability = { (3/5)*(2/3)*(¾)} + {(3/5)*(1/3)*(¼)}+{(2/5)*(2/3)*(¼)} 5/12
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ICRISAT deals with..........?
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