Question
Three persons. A, B and C. are given the same puzzle to
solve. The probability that A, B and C will solve the puzzle is. 3/5., 2/3., and 1/4respectively. Find the probability that exactly one of them will not solve the puzzleSolution
Probability of A solving the puzzle = 3/5 Therefore the probability of A not solving the puzzle = 1- (3/5) = 2/5 Probability of B solving the puzzle = 2/3 Therefore. Probability of B not solving the puzzle = 1/3 Probability of C solving the puzzle = ¼ Probability of C not solving a puzzle= ¾ Therefore, required probability = { (3/5)*(2/3)*(¾)} + {(3/5)*(1/3)*(¼)}+{(2/5)*(2/3)*(¼)} 5/12
How many Zeros can be formed by multiplying 10×20×30×40×…………….× 3000
The sum of eight consecutive even numbers of set-A is 416. What is the sum of five consecutive numbers of another set whose lowest number is 18 more tha...
In a group of three numbers first is double of second and half of third. The average of three numbers is 56. Find the difference between the first numb...
Anil and Ashish receive Rs.1500 for work of 6 days. If Anil is 4 times efficient than Ashish, then find the daily wage received by Ashish.
Choose the number which is different from the group.
Raj scored 140 marks in a test getting 3 marks for each right answer and losing 1 mark for each wrong answer, had 4 marks been awarded for each correct...
If x and y are the two digits of the number 115xy such that this number is divisible by 90, then the value of x + y is:
Find the largest number which should replace 'x' in the number 7184x8, to make the number divisible by 4.
- Find the highest value of (x + y) if '7x482y6' is divisible by 12.
'M' is the largest three-digit number that leaves 3 as a remainder when divided by 9, 12 and 5, Find the sum of digits of 'M'.
Relevant for Exams:
