In a mixture of milk and water, the amount of milk is 37 ml greater than the amount of water. After 75% of the mixture is removed and 10.75 ml of milk is added, the milk becomes 40% more than the water in the resulting mixture. Determine the initial quantity of the mixture.

ATQ, Let the quantity of water in the initial mixture be '4m' ml So, quantity of milk in the initial mixture = (4m + 37) ml Quantity of water after removing 75% mixture = 4m × 0.25 = 'm' ml So, quantity of milk after removing 75% mixture = (4m + 37) × 0.25 = (m + 9.25) ml Quantity of milk after adding 10.75 ml of milk = (m + 9.25 + 10.75) = (m + 20) ATQ. (m + 20) ÷ m = (140/100) Or, 5 × (m + 20) = 7m Or, 100 = (7m - 5m) Or, 2m = 100 So, 'm' = 50 Therefore, initial quantity of mixture = (4m + 4m + 37) = (8m + 37) ml = (8 × 50 + 37) = 437 ml