Question
A thief saw a policeman and he started running at a
speed of 12 m/s. After a certain time, the policeman starts running behind the thief at a speed of 18 m/s. If the policeman covered a 540 m distance to catch the thief, the time (in seconds) after which the policeman started running is:Solution
Given: Thief speed = 12 m/s Policeman speed = 18 m/s Policeman runs 540 m Let delay time = t seconds Policeman’s running time: = 540 ÷ 18 = 30 sec Thief’s total running time: = t + 30 Distance thief runs: = 12 × (t + 30) Set equal to 540: 12(t + 30) = 540 t + 30 = 45 t = 15
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