Question
‘x’ sold two cars at same price, one of them at 10%
profit. ‘x’ incurred total loss of 12% in overall transaction. What was the approximate profit/loss incurred on the other car?(calculate approx value)Solution
ATQ, Let SP = 2x CP of both cars = 2x × (100/88) = (25x/11) CP of FIRST car = x × (100/110) = (10x/11) CP of SECOND car = (25x/11) - (10x/11) = (15x/11) Loss in cost = (15x/11) - x = (4x/11) Loss in % = ((4x/11) × 100)/(15x/11) = 80/3 = 26.67% or approx 27% loss
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