Question
If 56 ÷14 x 22 –12 x 6 ÷ 3 +10 = z, then
find the value of z.Solution
56 ÷14 x 22 –12 x 6 ÷ 3 +10 = z 4 x 22 –12 x 2 +10 = z 4 x 22 –12 x 2 +10 = z 16-24+10=z Z=2.
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