Question
In a circle, chords AB and CD are produced to meet at E.
outside the circle. If AB = 9 cm and AE = 12 cm and ED = 4 cm, then what is the length of the chord CD?Solution
According to the concept, AE × BE = CE × ED 12 x 3 = CE × 4  CE=9 Now, CE = CD + ED 9 = CD + 4 9-4=CD  CD=5 The length of the chord CD is 5 cm. 
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