Question

In a circle, chords AB and CD are produced to meet at E. outside the circle. If AB = 9 cm and AE = 12 cm and ED = 4 cm, then what is the length of the chord CD?

According to the concept, AE BE CE ED 12 x 3 CE 4 CE9 Now, CE CD ED 9 CD 4 9-4CD CD5 The length of the chord CD is 5 cm.

A 5.5 cm

B 5 cm

C 4 cm

D 4.5 cm

Detailed Solution