Question
Pipe A fills a tank in 24 hours. Pipe A and B together fill it in 8 hours. Pipe B and C together also fill it in 8 hours. Find the time taken by A, B and C together.
Solution
ATQ, A = 1/24 B = 1/8 − 1/24 B = (3 − 1)/24 = 2/24 = 1/12 B + C = 1/8 C = 1/8 − 1/12 C = (3 − 2)/24 = 1/24 A + B + C = 1/24 + 1/12 + 1/24 = (1 + 2 + 1)/24 = 4/24 Required time = 24/4 hours = 6 hours
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