Question
Pipe ‘M’ and pipe ‘N’ can fill a tank alone in 20 hours and 40 hours, respectively. If both pipes are opened together and pipe ‘M’ is closed after 5 hours, then find the time taken by pipe ‘N’ to fill the remaining portion alone.
Solution
Let the capacity of the tank be 40 units (LCM of 20 and 40) Efficiency of pipe ‘M’ = 40 ÷ 20 = 2 unit/hour
Efficiency of pipe ‘N’ = 40 ÷ 40 = 1 unit/hour Let pipe ‘N’ fill the remaining portion in x hours. ATQ, 5 × (2 + 1) + 1x = 40 Or, 15 + x = 40 Or, x = 25 Therefore, required time taken = 25 hours
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