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ATQ, Let the total capacity of the tank = 200 units Efficiency of pipes (G + H) = 200/40 = 5 units/hour Efficiency of pipes (H + I) = 200/25 = 8 units/hour Let the efficiency of pipe ‘G’ = x units/hour Therefore, efficiency of pipe ‘I’ = 2x units/hour Therefore, 2x – x = 8 – 5 Or, x = 3 Therefore, efficiency of pipe ‘H’ = 5 – 3 = 2 units/hour Time taken by pipe ‘H’ to fill the tank alone = 200/2 = 100 hours
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