Question
Pipe βXβ alone can fill a tank in 20 hours. When
pipe βXβ and βYβ are opened together, they can fill 60% of the same tank in 6 hours. Find the time taken by pipe βYβ alone to fill 80% of the same tank.Solution
ATQ; Time taken by pipes βXβ and βYβ together to fill 100% of the tank = 6 Γ· 0.6 = 10 hours Let the capacity of the tank be 100 litres. {LCM (20 and 10)} Efficiency of pipe βXβ = (100/20) = 5 litres/hour Efficiency of pipe βXβ and βYβ together = (100/10) = 10 litres/hour Efficiency of pipe βYβ = 10 β 5 = 5 litres/hour Time taken by pipe βYβ to fill 80% of the tank = (100 Γ 0.8)/5 = 16 hours
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
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