Question
Tap A can fill a tank in 20 hours and tap B can empty it
is 25 hours. Tap A starts filling and they opened for 1 hour each alternatively in what time will the tank be full?Solution
Let tank capacity is = 100 ltr LCM of 20 and 25 So tap A can fill it in 20 hours ∴ Tap A can fill per hours = 100/20 = 5 ltr Tap B can empty it in 25 hours ∴ Tap B can empty per hours = 100/25 = 4 ltr Tank filled after 2 hour = 5 - 4 = 1 ltr (If taps open alternatively) In last hour tap A fill tank 5 ltr So rest part of tank need to be filled is = 100 - 5 = 95 ltr In 2 hours tank filled = 1 ltr So 95 ltr to be filled in = 95 × 2 = 190 ∴ So total time = 190 + 1 = 191 hours
5, 18, 39, 68, 105, ?
230 192 172 ? 122 100
...5, 6, 14, 45, 184, ?
15, 23, 30, 36, 41, ?
3, 8, 27, 124, ?
1236, 1445, 1675, 1933, 2226, ?
13, 29, 65, 129, ?, 373
12, 33, 45, 78, 123, 201, ?
What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
250, 279, 311, 349, 396, ?
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