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Start learning 50% faster. Sign in nowLet the efficiencies of 'P' and 'Q' be '3a' and '5a' litres/hour respectively. Total capacity of given tank = (3a + 5a) X 16 = '128a' litres Capacity of tank to be filled by pipe 'P' = (1.5) X 128a = '192a' litres New efficiency of pipe 'P' = 2 X 3a = '6a' litres/hour Required time = (192a/6a) = 32 hours
IMPLEMENT
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