Question
The efficiencies of two inlet pipes, 'P' and 'Q', are in
the ratio of 3:5, respectively. When both pipes are open together, the tank is filled in 16 hours. Now, if the efficiency of pipe 'P' is increased by 100%, how much time will it take for pipe 'P' to fill a tank that has 50% more capacity than the original tank?Solution
Let the efficiencies of 'P' and 'Q' be '3a' and '5a' litres/hour respectively. Total capacity of given tank = (3a + 5a) X 16 = '128a' litres Capacity of tank to be filled by pipe 'P' = (1.5) X 128a = '192a' litres New efficiency of pipe 'P' = 2 X 3a = '6a' litres/hour Required time = (192a/6a) = 32 hours
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