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      Question

      There are 3 identical toys and 4 identical books. How many

      distinct arrangements are possible on a shelf such that all three toys do not appear together?
      A 35 Correct Answer Incorrect Answer
      B 30 Correct Answer Incorrect Answer
      C 21 Correct Answer Incorrect Answer
      D 28 Correct Answer Incorrect Answer
      E 24 Correct Answer Incorrect Answer

      Solution

      Total = 7! / (3! * 4!) = 35
      Toys together: 1 block + 4 books = 5! / 4! = 5
      Required = 35 - 5 = 30

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