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    Question

    There are 3 identical toys and 4 identical books. How many

    distinct arrangements are possible on a shelf such that all three toys do not appear together?
    A 35 Correct Answer Incorrect Answer
    B 30 Correct Answer Incorrect Answer
    C 21 Correct Answer Incorrect Answer
    D 28 Correct Answer Incorrect Answer
    E 24 Correct Answer Incorrect Answer

    Solution

    Total = 7! / (3! * 4!) = 35
    Toys together: 1 block + 4 books = 5! / 4! = 5
    Required = 35 - 5 = 30

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