Question
A group consists of 6 boys and 8 girls. In how many ways
can 2 boys and 3 girls be selected from the group?Solution
Required number of ways = 6 C 2 × 8 C 3
= (6! / (2! × 4!)) × (8! / (3! × 5!))
= 15 × 56 = 840
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