Question
A group consists of 6 boys and 8 girls. In how many ways
can 2 boys and 3 girls be selected from the group?Solution
Required number of ways = 6 C 2 × 8 C 3
= (6! / (2! × 4!)) × (8! / (3! × 5!))
= 15 × 56 = 840
More Permutation and combination Questions
(92.03 + 117.98) ÷ 14.211 = 89.9 – 30.23% of ?
(512) (2/3) × √64 ÷ (512) (1/3) = (64) (?/2) ÷ (2)6
540 ÷ 6 + 25 % of 120 + ? * 8 = 72 * √9
2/5 of 3/4 of 7/9 of 7200 = ?
2222 ÷ 22 + 992 ÷ 16 + 650 ÷ 25 = ?
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 
20% of 150 + 30 X 4 = ? X 5
√1369 + √1024 + √841 =(?)2 − 46
{(8× 8 + 3 × 39) - 620 ÷ 20} = ?
Relevant for Exams:
