Question
A group consists of 6 boys and 8 girls. In how many ways
can 2 boys and 3 girls be selected from the group?Solution
Required number of ways = 6 C 2 × 8 C 3
= (6! / (2! × 4!)) × (8! / (3! × 5!))
= 15 × 56 = 840
More Permutation and combination Questions
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
(29.892 × √290) + 32.98 × 6.91 = ?
44.84% of 799.94 + (625.21 ÷ 24.91) – √(224.77) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
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