Question
In a group of 5 boys and 4 girls, 5 students have to be
selected. In how many ways it can be done so that only 2 boys are included.Solution
=> 5C2 × 4C3 = [5!/(5 -2)! 2!] × [4!/(4 -3)! 3!] => [5!/3! 2!] × [4!/1! 3!] => 40 ways
More Permutation and combination Questions
(13.156)2 + (3.945)2 + (5.903)3 = ?
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
1726 1/3 + 40% of 1849.889 + 15.12 × 18.25 = ?
2470.03 ÷ 64.98 x 39.9 = ? + 20.32
583.9 + 1519.98 - 445.21 = 1150.011 + ?
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
If the length of one side of a rhombus is 16cm then find its surface area. (use √ 3 = 1.732)
5466.97 - 3245.01 + 1122.99 = ? + 2309.99
? = (5.8)2 + (8.9)2 + (4.7) 2 + 24.7% of 20