Question
In a group of 5 boys and 4 girls, 5 students have to be
selected. In how many ways it can be done so that only 2 boys are included.Solution
=> 5C2 × 4C3 = [5!/(5 -2)! 2!] × [4!/(4 -3)! 3!] => [5!/3! 2!] × [4!/1! 3!] => 40 ways
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