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There are 8 digits 1, 2, 0, 2, 4, 1, 2, 4 in which 1 occurs 2 times, 2 occurs 3 times and 4 occurs 2 times ∴ Number of 8 digit numbers = 8!/(2! ×3! ×2!) = 1680 But out of these 1680 numbers there are some numbers which begin with ‘0’ and they are not 8 digit numbers The numbers of such numbers beginning with ‘0’ = 7!/(2! ×3! ×2!) = 210 Hence the required number of 8 digit numbers = 1680 – 210 = 1470
A number, when divided by 64, leaves a remainder of 47. What will be the remainder when it is divided by 16?
What least number must be added to 6834 to get a number exactly divisible by 18?
There are 3 natural numbers. If the average of any 2 numbers is added with the third number 34, 30 and 28 will be obtained. Find the numbers.
If the number 985212m8 is completely divisible by 11, then the smallest whole number in place of ‘m’ would be:
What is the difference between 3/5 of 150 and 1/2 of 300?
How much greater than 30 is the result when twice the sum of the first five prime numbers is subtracted from the largest two-digit prime number?
The divisor is 35 times the quotient and 7 times the remainder. If the quotient is 18, the dividend is :
If (3/4)th of a number is subtracted from (5/6)th of that number, then the resultant will be (2/6). Find the number.
What is the average of all the prime numbers which are less than 35?
Akhilesh has a collection of toys, and he tries arranging them in different group sizes. Whenever he groups them in pairs (2s), triplets (3s), sets of f...
